Вариант 5 №2 from itertools import * s = product('СВЯТОСЛАВ', repeat = 7) b = [] for x in s: d = ''.join(x) if d.count('Я')+d.count('О')+d.count('А') > d.count('С')+d.count('В')+d.count('Т')+d.count('Л'): b.append(d) print(len(b)) №4 from ipaddress import * net = ip_network('170.180.190.200/20', 0) b = [] for x in net: d = hex(int(x))[2:] if d[0] == d[-1]: s = int(d, 16) b.append(s) print(str(max(b)).replace('.', '')) №6 def F(n): d = oct(n)[2:] if n%3 == 0: d = d + d[-2:] else: d = d[:1] + d return int(d, 8) print(F(15)) №1 (Мангуст) А = 0 Г = 1 М = 2 Н = 3 С = 4 Т = 5 У = 6 ТУСММ - 56422 №3 from ipaddress import * net = ip_network('139.190.87.229/21', 0) print(str(net[-2]).replace('.', '')) №5 m = [x for x in data if 100<= abs(x) <= 999 and (x//100) * (x%10) >= 0] print(sum(m)) 8 варик №1 from itertools import product ab=product("АГИНРТ", repeat=6) k=0 for x in ab: s = "".join(x) k+=1 if k % 2 != 0 and s[0] not in "АИГ" and s.count("А") == 1: print(k) break ВАРИАНТ 1 from itertools import * data = product("САМОКАТ", repeat=7) c=0 for x in data: s = ''.join(x) if "САМ" in s and "АСАМА" in s or "ОСАМО" in s: c+=1 print(c) 3 задача from ipaddress import* net=ip_network("215.143.108.204/255.255.192.0",0) print(max(net)) #4 варик 8 from ipaddress import * net = ip_network("99.165.134.0/255.255.254.0") c = 0 for i in net: s = bin(int(i))[2:].zfill(32) if s.count('1')%3==0: c += 1 print(c)